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/*jshint esversion: 6 */
"use strict";
const assert = require('assert');
const lobject = require('./lobject.js');
const lua = require('./lua.js');
const CT = lua.constant_types;
const nil = require('./ldo.js').nil;
const Table = lobject.Table;
const TValue = lobject.TValue;
Table.prototype.ordered_intindexes = function() {
return [...this.value.keys()]
.filter(e => typeof e === 'number' && e % 1 === 0) // Only integer indexes
.sort();
};
Table.prototype.ordered_indexes = function() {
return [...this.value.keys()]
.sort(function(a, b) {
if (typeof a !== "number") return 1;
if (typeof b !== "number") return -1;
return a > b ? 1 : -1;
});
};
/*
** Try to find a boundary in table 't'. A 'boundary' is an integer index
** such that t[i] is non-nil and t[i+1] is nil (and 0 if t[1] is nil).
*/
Table.prototype.luaH_getn = function() {
// TODO: is this costly ?
let indexes = this.ordered_intindexes();
let len = indexes.length;
for (let i = 0; i < len; i++) {
let key = indexes[i];
if (!this.__index(this, key).ttisnil() // t[i] is non-nil
&& (i === len - 1 || this.__index(this, indexes[i + 1]).ttisnil())) { // t[i+1] is nil or is the last integer indexed element
return indexes[i] + 1;
}
}
return 0;
};
Table.prototype.luaH_next = function(L, keyI) {
let keyO = L.stack[keyI];
let key = Table.keyValue(keyO);
let indexes = this.ordered_indexes();
if (indexes.length === 0) return 0;
let i = indexes.indexOf(key);
if ((i >= 0 || key === null) && i < indexes.length - 1) {
if (key === null) i = -1;
let nidx = indexes[i+1];
let tnidx = typeof nidx;
if (tnidx === 'number' && nidx % 1 === 0)
L.stack[keyI] = new TValue(CT.LUA_TNUMINT, indexes[i + 1]);
else if (tnidx === 'string')
L.stack[keyI] = new TValue(CT.LUA_TLNGSTR, indexes[i + 1].split('|').map(e => Number.parseInt(e)).slice(0, -1));
else
L.stack[keyI] = indexes[i + 1];
L.stack[keyI + 1] = this.value.get(indexes[i + 1]);
return 1;
}
return 0;
};
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